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Python Python Basics (2015) Number Game App Even or Odd

function argument from user input?

Hi everyone,

I've been struggling on this one, and would like to request for some insights. Can you kindly tell me what I'm doing wrong here:

def even_odd(numbr): usr_input = int(input("Please give me a number: ")) if (usr_input % 2 == 0): print("Thanks, you just gave me an EVEN number !") return True else: print("Thanks, you just gave me an ODD number !")

return False

Thanks in advance for any help you can provide. Regards, -Conrad

def even_odd(numbr):
    usr_input = int(input("Please give me a number: "))
    if (usr_input % 2 == 0):
        return True
        return False

2 Answers

Stuart Wright
Stuart Wright
41,118 Points

The challenge asks you to pass a number to the function, and return True if that number is even or False if it is odd.

You have done something different. You have passed a number (which you have named 'numbr') to your function, but then you don't do anything with it. Instead you ask the user for a number, which you are not required to do.

So to fix your code, simply delete your user input line, and change your if statement to check if 'numbr' rather than 'usr_input' is odd/even.

Awesome ! It worked ! Thank you, Stuart, for your help.