function logTeacher(teacher) {
console.log(`${person.name} - ${teacher.role}`); }

Question

In this course the following code is used.
const person = {
    name: 'Andrew Chalkley',
    role: 'JavaScript Teacher' }
function logTeacher(teacher) {
    console.log(${teacher.name} - ${teacher.role}); }
logTeacher(person);
Q: my question is this. from what i understand this function ' teacher' is using properties from the object literal person. in the line  console.log(${teacher.name} - ${teacher.role}); }
i would have tought that the code should be:
 console.log(${person.name} - ${peron.role}); } . both code options give the same results.
why does ${teacher.name} and  ${person.name} give the same results?

jb30 · Accepted Answer

${teacher.name} and ${person.name} give the same result in this case because logTeacher is only called once, with the argument person, in the line logTeacher(person);.
If you change the argument passed into the function, the output will change.
javascript
const person = { name: 'Andrew Chalkley', role: 'JavaScript Teacher' };
logTeacher(person); // outputs 'Andrew Chalkley - JavaScript Teacher'
const person1 = { name: 'Max van den Berge', role: 'JavaScript Student' };
logTeacher(person1); // outputs 'Max van den Berge - JavaScript Student'

If you change the logTeacher function to
javascript
function logTeacher(teacher) {
    console.log(`${person.name} - ${person.role}`); 
}

then the teacher parameter will be ignored in the output:
javascript
const person = { name: 'Andrew Chalkley', role: 'JavaScript Teacher' };
logTeacher(person); // outputs 'Andrew Chalkley - JavaScript Teacher'
const person1 = { name: 'Max van den Berge', role: 'JavaScript Student' };
logTeacher(person1); // outputs 'Andrew Chalkley - JavaScript Teacher'

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Max van den Berge

Max van den Berge

function logTeacher(teacher) { console.log(`${person.name} - ${teacher.role}`); }

1 Answer

jb30

jb30

Max van den Berge

Max van den Berge