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iOS Swift 2.0 Functions Function Parameters Function Parameters

andrew field
andrew field
3,364 Points

Function parameter challenge problem

In this task we're going to write a simple function that takes two numbers and returns the remainder of dividing one number by the other.

Step 1: Declare a function named getRemainder that takes two parameters, aand b, both of type Int, and returns the value, also of type Int, obtained by carrying out the operation a modulo b. In case you've forgotten, the modulo operator is also called the remainder operator.

Step 2: The local names of the parameters are convenient but they make it hard to figure out the meaning of the function when we call it. Add two external names - value, for the first parameter and divisor for the second.

andrew field
andrew field
3,364 Points

sorry, my code is

func getRemainder (a value: Int, b divisor:Int) -> Int { return value % divisor }

4 Answers

Brendan Whiting
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Brendan Whiting
Front End Web Development Techdegree Graduate 84,738 Points

They want to external names to be 'value' and 'divisor' and the internal names to be 'a' and 'b'. You have it the other way around.

Solution:

func getRemainder(value a: Int, divisor b: Int) -> Int {
  return a % b
}

Should be noted that documentation suggests other way around..

Yeah, I had my external and local names backwards.

Rich Braymiller
Rich Braymiller
7,119 Points

just for the record my code:

func getRemainder(a value: Int, b divisor: Int) -> Int { return a % b }

would not pass but

func getRemainder(value a: Int, divisor b: Int) -> Int { return a % b }

DID ugh ugh