Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

iOS Swift 2.0 Functions Function Parameters Function Parameters

andrew field
andrew field
3,364 Points

Function parameter challenge problem

In this task we're going to write a simple function that takes two numbers and returns the remainder of dividing one number by the other.

Step 1: Declare a function named getRemainder that takes two parameters, aand b, both of type Int, and returns the value, also of type Int, obtained by carrying out the operation a modulo b. In case you've forgotten, the modulo operator is also called the remainder operator.

Step 2: The local names of the parameters are convenient but they make it hard to figure out the meaning of the function when we call it. Add two external names - value, for the first parameter and divisor for the second.

andrew field
andrew field
3,364 Points

sorry, my code is

func getRemainder (a value: Int, b divisor:Int) -> Int { return value % divisor }

4 Answers

Brendan Whiting
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Brendan Whiting
Front End Web Development Techdegree Graduate 84,735 Points

They want to external names to be 'value' and 'divisor' and the internal names to be 'a' and 'b'. You have it the other way around.

Solution:

func getRemainder(value a: Int, divisor b: Int) -> Int {
  return a % b
}

Should be noted that documentation suggests other way around..

Yeah, I had my external and local names backwards.

Rich Braymiller
Rich Braymiller
7,119 Points

just for the record my code:

func getRemainder(a value: Int, b divisor: Int) -> Int { return a % b }

would not pass but

func getRemainder(value a: Int, divisor b: Int) -> Int { return a % b }

DID ugh ugh