Function that return the high number

Hey Maor Tzabari,

Although your function is syntactically correct, it is less efficient than the actual answer because it uses more memory and isn't returning anything. You only need two arguments: an input1 and input2. There's no need for a variable named high because you want to return the higher number.

For example, let's say I were making my own "min" function:

//Create the function called min with two arguments: an input1 and an input2
function min(input1,input2){
//If input1 is less than input2, it is the minimum so
  if (input1 < input2) {
   //Return input1 
   return input1;
  } 
//Otherwise, input2 must be smaller so
  else {
   //Return input2
    return input2;
  }
}

That example above is very similar to the way you should construct your max function. I don't want to give you the answer directly because I want you to see what is happening and figure it out for yourself. It is far more satisfying that way, as well. :)

You've not passed any numeric arguments to the function.

That is to say: you've put no numbers in, so the function has nothing to compare against.

You've currently got :

max(high)

What you need is something like:

max(40, 76);

Also, there's no need to put high in the function arguments, just make it a variable and then return the value of that variable at the end of the function i.e.:

function max( input1, input2 ) {

  var num1 = parseInt(input1),
        num2 = parseInt(input2),
        high;

  if ( num1 > num2 ) {
    high = num1;
  }
  else {
    high = num2;
  }

return high;

}

max(40,76);

I did it also before, but it didn't work

What I'm saying, I did exactly like you efficient code before, and it still gave me error, that's why I changed my code, so you saw only this version of what i wrote. Anyway, I think I got it