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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Review Creating Reusable Code with Functions

Roberto Enea
Roberto Enea
3,558 Points
Posted by Roberto Enea
Roberto Enea
3,558 Points

function warning() { alert('Warning, warning, warning!'); } warning(); why i am not calling the function properly?

I am asked to call the function correctly. I think i did. But still the answer is wrong. Why? The function is taking no parameters so it seems that warning(); should work.

2 Answers

Austin Flagler
Austin Flagler
10,227 Points

I think that you are likely adding a semicolon at the end, but they already include one at the end that is hard to notice, so the answer would strictly be "warning()".

Roberto Enea
Roberto Enea
3,558 Points
Roberto Enea
Roberto Enea
3,558 Points

Thank you very much. Now i noticed it :) It is late in the night and my eyes are going wild. But the hunger...