I'm writing a program that takes three integer inputs: "Fuzz", "Bizz", and "Nezz".

Print numbers from 1 to the user's input for "Nezz". For the multiples of "Fuzz", print "Fuzz" instead of the number and for the multiples of "Bizz", print "Bizz" instead of the number. For numbers which are multiples of both "Fuzz" and "Bizz" print " FuzzBizz"

This is a working program and it's what I'm going for, but there are some things I don't get;

include <stdio.h>

include <stdlib.h>

int main() {

char nezzChar[4]; — // 

Why is it a char and not an int? Why is there an array of characters instead of just one value?

\ printf("Choose a number between 100 and 999 for Nezz and press [Enter]\n"); gets(nezzChar);

char fuzzChar[4];
printf("Choose a 1-digit number for Fuzz and press [Enter]:\n");
gets(fuzzChar);

char bizzChar[4]; 
printf("Choose a 1-digit number for Bizz and press [Enter]:\n");
gets(bizzChar);

int fuzz = atoi(fuzzChar); int bizz = atoi(bizzChar); int nezz = atoi(nezzChar); //

This converts char to int right? But why can’t the input be an int already?

\

int x; //

I don´t get this loop, when did x became Nezz?

\ for (x = 1; x <= nezz; x++) {

    if (x % fuzz == 0 & x % bizz == 0) {

        printf("FuzzBizz\n");

    }

    else if (x % fuzz == 0) {

        printf("Fuzz\n");

    } else if (x % bizz == 0)  {

        printf("Bizz\n");

    } else {

    printf("%d\n", x);

    }
}

}

Thanks for your help!