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JavaScript AJAX Basics (retiring) Programming AJAX Check for the correct ready state

Tiffany White
Tiffany White
5,373 Points
Posted by Tiffany White
Tiffany White
5,373 Points

getElementById('sidebar'); not passing.

My code for AJAX Basics Challenge Task one looks as follows. I don't know that I am doing wrong here?

app.js 
var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function() {
  if (xhr.readyState === 4) {
    if (xhr.status === 200) {
    }
  }
};
var ele = document.getElementById('sidebar');
xhr.open('GET', 'sidebar.html');
xhr.send();
index.html 
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>AJAX with JavaScript</title>
  <script src="app.js"></script>
</head>
<body>
  <div id="main">
    <h1>AJAX!</h1>
  </div>
  <div id="sidebar"></div>
</body>
</html>
Damien Watson
Damien Watson
27,419 Points
Damien Watson
Damien Watson
27,419 Points

Sam, if you could put your answers in 'answer' not 'comment', this will help people out if it's the correct answer. :)

1 Answer

Sam Okasha
Sam Okasha
10,343 Points
Sam Okasha
Sam Okasha
10,343 Points

Try this:

  document.getElementById("sidebar").innerHTML = request.responseText;

inside the if xhr === 200 statement. Without the .innerHTML it will just save the selected element in a variable whereas here you want to display the response on the page using .innerHTML