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JavaScript AJAX Basics (retiring) Programming AJAX Check for the correct ready state

Tiffany White
Tiffany White
5,373 Points

getElementById('sidebar'); not passing.

My code for AJAX Basics Challenge Task one looks as follows. I don't know that I am doing wrong here?

app.js
var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function() {
  if (xhr.readyState === 4) {
    if (xhr.status === 200) {
    }
  }
};
var ele = document.getElementById('sidebar');
xhr.open('GET', 'sidebar.html');
xhr.send();
index.html
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>AJAX with JavaScript</title>
  <script src="app.js"></script>
</head>
<body>
  <div id="main">
    <h1>AJAX!</h1>
  </div>
  <div id="sidebar"></div>
</body>
</html>
Damien Watson
Damien Watson
27,419 Points

Sam, if you could put your answers in 'answer' not 'comment', this will help people out if it's the correct answer. :)

1 Answer

Sam Okasha
Sam Okasha
10,343 Points

Try this:

  document.getElementById("sidebar").innerHTML = request.responseText;

inside the if xhr === 200 statement. Without the .innerHTML it will just save the selected element in a variable whereas here you want to display the response on the page using .innerHTML