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Trace Harris
Python Web Development Techdegree Graduate 22,065 PointsGetting an Error Hmm not finding the correct output did you remember to lowercase the string and split on whitespace
So with a bit of research on the forums here I found the answer and It was two fold I was not splitting on the whitespaces. (ie .split() native behavior) and I was not lowercasing the string at the proper location so my list variable should of been list = string.lower().split(), I would like to hear others take on this challenge and would like to find a more elegant solution maybe discuss how this may be done with packing a dictionary. or with the dict() function. Thanks for your time
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
string = "So So this is just a taste is just taste of what prob prob"
def word_count(string):
list = string.split(" ")
diction ={}
for item in list:
diction[item] = list.count(item)
return diction
word_count(string.lower())
1 Answer
Trace Harris
Python Web Development Techdegree Graduate 22,065 Pointsstring = "So So this is just a taste is just taste of what prob prob"
def word_count(string):
list = string.lower().split()
diction ={}
for item in list:
diction[item] = list.count(item)
return diction
word_count(string)