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Shelby Larson
33,317 PointsGetting and Storing JSON Code Challenge task 5
The question: Create a variable named my_plugin_profile. Assign it the JSON decoded value of the json_feed array's body index. Then return the my_plugin_profile variable.
My code: <?php
function my_plugin_get_profile($my_plugin_username) { $json_feed_url = 'http://myapi.net/' . $my_plugin_username . '.json'; $args = array('timeout' => 120); $json_feed = wp_remote_get( $json_feed_url, $args ); $wptreehouse_profile = json_decode( $json_feed['$my_plugin_profile'] ); return $json_feed['$my_plugin_profile']; }
?>
I don't understand what I'm doing wrong.
2 Answers
Jill Sheeks
11,169 PointsThis is what I used and it worked. <?php
function my_plugin_get_profile($my_plugin_username) { $json_feed_url = 'http://myapi.net/' . $my_plugin_username . '.json'; $args = array('timeout' => 120); $json_feed = wp_remote_get( $json_feed_url, $args ); $my_plugin_profile = json_decode( $json_feed['body'] ); return $my_plugin_profile; }
?>
Kenan Memis
47,314 PointsHi, The final part of your answer, the return statement, just replace it with the following:
return $my_plugin_profile;
matsum0t0
12,520 Pointsmatsum0t0
12,520 PointsHey there, I'm going to attempt to help you without giving you the answer. First "Create a variable named $my_plugin_profile." (not $wptreehouse_profile). Second "Assign it the JSON decoded value of the json_feed array's 'body' index" so your array[] needs a different value, extracted from the $json_feed. Lastly "Then return the my_plugin_profile variable." The $json_feed was already assigned to the $my_plugin_profile so you just need to return the my_plugin_profile variable. That may get you a little further, or you could be completely finished already. oh well.
M@