Python Python Sequences Sequence Iteration Iterating over Ranges

Mo Reese
Mo Reese
10,731 Points
Posted by Mo Reese
Mo Reese
10,731 Points

Getting back a "None"

I passed the challenge, but became confused when the editor refused to show me a preview & told me to 'check my code'. When i went to work spaces, all I got was: None None None... (x10) When I thought I would get [0, 1, 2, 3,etc].

my_list = []

for i in range(0, 10, 1):
    print (my_list.append(i))

Can someone please tell me what I am missing & why i did not get the expected result of a list with int 0 thru 9?

2 Answers

Vivian Tung
Vivian Tung
1,844 Points
Vivian Tung
Vivian Tung
1,844 Points

Hey! I thought this would give me the list too when I first looked at it. The trouble is that

my_list.append(i)

is a NoneType, meaning that it adds (i) to the list, but isn't the list itself. So printing that statement won't give anything other than None.

To get the full list, you could just separate the commands.

Hope this helped!

Mo Reese
Mo Reese
10,731 Points
Mo Reese
Mo Reese
10,731 Points

Ok, I see what you're saying about separating the commands, and when I ran:

my_list = []

for i in range(0, 10, 1):
    my_list.append(i)

print (my_list)

I did get the result that I expected... Thanks!

KRIS NIKOLAISEN
KRIS NIKOLAISEN
54,544 Points
KRIS NIKOLAISEN
KRIS NIKOLAISEN
54,544 Points

From the docs

You might have noticed that methods like insert, remove or sort that only modify the list have no return value printed – they return the default None. This is a design principle for all mutable data structures in Python.

Mo Reese
Mo Reese
10,731 Points
Mo Reese
Mo Reese
10,731 Points

Thanks for your response Kris. I'll use that link in the future!