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Jack Colosky
Courses Plus Student 2,263 PointsGetting error : Value of type 'string' does not conform to expected dictionary value type 'AnyObject
When I create my dictionary and define the type, I get this error : Value of type 'string' does not conform to expected dictionary value type 'AnyObject.
let joeSmith: [String : AnyObject] = ["Name":"Joe Smith", "Experience": true, "Parent Guardian": "Mr. & Mrs. Smith"] let jillTanner:[String : AnyObject] = ["Name" : "Jill Tanner","Experience": true, "Parent Guardian": "Clara Tanner"]
please help,
Thanks,
Jack Colosky
2 Answers
Nathan F.
30,773 PointsHi Jack,
You can do some reading about the differences between Any and AnyObject in Swift at the link provided. This was also the approach I was going to take for this project, but I decided to keep things simple and work around everything as strings.
In any case, the short answer is that you should use [String: Any] not [String: AnyObject]. If I understand how types work in Swift.... String is not a class. It's a value type, or a Struct. AnyObject only works with classes, like Objective-C's NSString. Any will allow any value at all, not just classes.
Nathan F.
30,773 PointsHey there, sure I can give you a pointer. Actually the error is telling you exactly what you need to know. ;)
You are getting Value of type '[String, Any]' has no member 'append' because you are calling the append() method on a dictionary, not an array. Check how you've defined your experPlayers and unexperPlayers constants:
experPlayers : [String : AnyObject] <-- this is a dictionary
What you want is an Array of dictionaries, so add another set of braces: [[String : AnyObject]]
One last hint: you've defined your experPlayers and unexperPlayers as constants using let. This means they won't and can't change. Are you sure that's what you want? :)
Best of luck!
Jack Colosky
Courses Plus Student 2,263 PointsThank you sm! reallllllly appreciate it
Nathan F.
30,773 PointsYou're very very welcome!
Jack Colosky
Courses Plus Student 2,263 PointsJack Colosky
Courses Plus Student 2,263 PointsThank you sm! I also had one other question if you wouldn't mind.
I'm getting this error : Value of type '[String, Any]' has no member 'append'
// All the players have there own dictonary to store their name, height, soccer experience, and guardians name
let jSmith : [String : Any] = ["Name" : "Joe Smith", "Height" : 42, "Soccer Expo" : true, "Guardian" : "Jim and Jan Smith"] let jTanner : [String : Any] = ["Name" : "Jill Tanner", "Height" : 36, "Soccer Expo" : true, "Guardian" : "Clara Tanner"] let bBon : [String : Any] = ["Name" : "Bill Bon", "Height" : 43, "Soccer Expo" : true, "Guardian" : "Sara and Jenny Bon"] let eGordan : [String : Any] = ["Name" : "Eva Gordan", "Height" : 45, "Soccer Expo" : false, "Guardian" : "Wendy and Mike Gordan"] let mGill : [String : Any] = ["Name" : "Matt Gill", "Height" : 40, "Soccer Expo" : false, "Guardian" : "Charles and Sylvia Gill"] let kStein : [String : Any] = ["Name" : "Kimmy Stein", "Height" : 41, "Soccer Expo" : false, "Guardain" : "Bill and Hillary Stein"]
// An array to store all the dictonaries
let playerRoster = [jSmith, jTanner, bBon, eGordan, mGill, kStein]
//teams
let sharks : [String : Any] = [:] let dragons : [String : Any] = [:] let raptors : [String : Any] = [:]
//The types of players
let experPlayers : [String : AnyObject] = [:] let unexperPlayers : [String : AnyObject] = [:]
for player in playerRoster { if player["Soccer Expo"] as! Bool == true { experPlayers.append(player) } else { unexperPlayers.append(player) } }
sorry for all the questions,
thanks,
Jack Colosky