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Python Regular Expressions in Python Introduction to Regular Expressions Negated Numbers

Ron Tovbin
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.a{fill-rule:evenodd;}techdegree
Ron Tovbin
Python Web Development Techdegree Student 6,268 Points
Posted by Ron Tovbin
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Ron Tovbin
Python Web Development Techdegree Student 6,268 Points

Getting stuck here

Any help here would be appreciated.

negate.py 
import re

string = '1234567890'

good_numbers = re.findall(r"""
               \d+
               [^5678]+
               """,string,re.X)

2 Answers

David Deberry
David Deberry
5,447 Points
David Deberry
David Deberry
5,447 Points

Hey I searched and found this as an answer. Do not upvote my answer because sadly it is not my code so I do not deserve it lol But I hope this helps. 

good_numbers = re.findall(r'\d[,9][^567]', string)
Iain Simmons
MOD
Iain Simmons
Treehouse Moderator 32,305 Points
Iain Simmons
Iain Simmons
Treehouse Moderator 32,305 Points

I think you might be overcomplicating things…

Just use the negated character class ([^notme]). You don't need any modifiers.

Also, I think the range of characters you're not meant to include is wrong. Your code has 5678, but it should only be 567.

Let us know how it goes!