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Ron TovbinPython Web Development Techdegree Student 6,268 Points
Getting stuck here
Any help here would be appreciated.
import re string = '1234567890' good_numbers = re.findall(r""" \d+ [^5678]+ """,string,re.X)
David Deberry5,447 Points
Hey I searched and found this as an answer. Do not upvote my answer because sadly it is not my code so I do not deserve it lol But I hope this helps.
good_numbers = re.findall(r'\d[,9][^567]', string)
I think you might be overcomplicating things…
Just use the negated character class (
[^notme]). You don't need any modifiers.
Also, I think the range of characters you're not meant to include is wrong. Your code has
5678, but it should only be
Let us know how it goes!