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travis ueki2,102 Points
Given a list of [a, b, c, d] How can you use .pop() to remove a c and .insert() to place at 0 index in one line of code
The directions say that this can be accomplished in one step. Does anyone have example code to demonstrate this?
the_list = ["a", 2, 3, 1, False, [1, 2, 3]] # Your code goes below here def new_list(): x = the_list.pop(3) the_list.insert(1, 0) new_list() > # Update > - I got the following to work, however, it feels hacky.. the_list = ["a", 2, 3, 1, False, [1, 2, 3]] # Your code goes below here newItem = the_list.pop(3) the_list.insert(0, newItem)
Chris FreemanTreehouse Moderator 68,064 Points
You have the code, now combine the lines:
newItem = the_list.pop(3) the_list.insert(0, newItem) # becomes the_list.insert(0, the_list.pop(3))