Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Basics (2015) Number Game App Squared

Maor Beeri
Maor Beeri
2,154 Points
Posted by Maor Beeri
Maor Beeri
2,154 Points

got a problem

I get this message error and don't know what to do :( need someone's assistance

squared.py 
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def squared (x):
    try:
       num = int(x)
    except ValueError:
        return num * len(num)
    else:
        return num*num

2 Answers

Steven Parker
Steven Parker
229,708 Points
Steven Parker
Steven Parker
229,708 Points

You're very close! But when the exception occurs, the variable "num" does not get assigned. So the code in the exception block should work with argument "x" directly instead.

Maor Beeri
Maor Beeri
2,154 Points
Maor Beeri
Maor Beeri
2,154 Points

oh now I understand thanks a lot!

Dave StSomeWhere
Dave StSomeWhere
19,870 Points
Dave StSomeWhere
Dave StSomeWhere
19,870 Points

Double check what you are doing to handle the exception and pay attention to the bummer error message, it is telling you the issue.