Welcome to the Treehouse Community
The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.
Maor Beeri2,154 Points
got a problem
I get this message error and don't know what to do :( need someone's assistance
# EXAMPLES # squared(5) would return 25 # squared("2") would return 4 # squared("tim") would return "timtimtim" def squared (x): try: num = int(x) except ValueError: return num * len(num) else: return num*num
Steven Parker216,136 Points
You're very close! But when the exception occurs, the variable "num" does not get assigned. So the code in the exception block should work with argument "x" directly instead.
Dave StSomeWhere19,822 Points
Double check what you are doing to handle the exception and pay attention to the bummer error message, it is telling you the issue.