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Min He789 Points
for group in musical_groups: s = "," print(s.join(group))
musical_groups = [ ["Ad Rock", "MCA", "Mike D."], ["John Lennon", "Paul McCartney", "Ringo Starr", "George Harrison"], ["Salt", "Peppa", "Spinderella"], ["Rivers Cuomo", "Patrick Wilson", "Brian Bell", "Scott Shriner"], ["Chuck D.", "Flavor Flav", "Professor Griff", "Khari Winn", "DJ Lord"], ["Axl Rose", "Slash", "Duff McKagan", "Steven Adler"], ["Run", "DMC", "Jam Master Jay"], ] s: s = "," print(s.join(group))for group in musical_group
Chris FreemanTreehouse Moderator 68,404 Points
Hey Min He, your solution is very cleaver!
With some modifications, I was able to get your code to produce the expected correct output. I needed to create separate lines instead of a list of strings.
s = ", " print(s.join([", ".join(group) for group in musical_groups]))
Ad Rock, MCA, Mike D. John Lennon, Paul McCartney, Ringo Starr, George Harrison Salt, Peppa, Spinderella Rivers Cuomo, Patrick Wilson, Brian Bell, Scott Shriner Chuck D., Flavor Flav, Professor Griff, Khari Winn, DJ Lord Axl Rose, Slash, Duff McKagan, Steven Adler Run, DMC, Jam Master Jay
However, including the corrections doesn’t pass because the checker doesn’t like the unexpected variable
s and is looking for a regular for loop and not a list comprehension.
Can you figure out how to get the same output using a regular for loop with the variable
Post back if you need more help. Good luck!!!