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Java

Handling exceptions task

I'm not sure what i'm doing wrong in this code.

public class Main {
    public static void main(String[] args) {
        GoKart kart = new GoKart("yellow");
        if (kart.isBatteryEmpty()) {
          System.out.println("The battery is empty");
        }
        kart.drive(2);
      try { 
        kart.drive(3);
        System.out.println("Only one lap per bar"); 
      } catch (IllegalArgumentException iae) {
       System.out.println("Limit exceeded!");
       System.out.printf("The error was: %s\n", iae.getMessage());
      }
    }
}

1 Answer

Andrew Winkler
Andrew Winkler
37,737 Points

There's a lot going on here & in this exercise in general. here is part 2 of the code challenge. You may have labeled your exceptions differently, but even so I anticipate you are "try"ing too much ;D

If you want to read up, here's the oracle documentation.

public class Main {
    public static void main(String[] args) {
        GoKart kart = new GoKart("yellow");
        if (kart.isBatteryEmpty()) {
          System.out.println("The battery is empty");
        }
      // wrap potentially dangerous code in the try block
      try {
        kart.drive(2);
      } 
      // catch an illegal argument exception e and use e to get the message
      catch (IllegalArgumentException e) {
        System.out.println(e.getMessage());
      }
    }
}