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Start your free trialEddie Licea
1,610 PointsHaving trouble with my code. I'm getting this error: invalid literal for int() with base 10: 'e'.
TICKET_PRICE = 10
tickets_remaining = 100
while tickets_remaining >= 1:
print("There are {} tickets remaining.".format(tickets_remaining))
name = input("What is your name? ")
number_of_tickets = input("How many tickets would you like to buy, {}? ".format(name))
#Expect a ValueError to happen and hande it appropriately... Remember to test it out
try:
number_of_tickets = int(number_of_tickets)
#Raise a avalue error if the request is for more tickets that are available
if number_of_tickets > tickets_remaining:
raise ValueError("There are only {} tickets remaining".format(tickets_remaining))
except ValueError as err:
#include the error text in the output
print("Oh no! We ran into an issue. {}. Please try again...".format(err))
else:
math = number_of_tickets * TICKET_PRICE
print("Your total is ${}".format(math))
proceed = input("Would you like to proceed? Y/N? ")
if proceed.lower() == "y":
# TODO: Gather credit card information and process it.
print("SOLD!")
tickets_remaining -= number_of_tickets
else:
print("Thank you anyway {}".format(name))
print("Sorry the tickets are sold out")
I don't get what is going on. I type in blue when I am prompted for the number of tickets, i'm expecting the value error to show up as I set it up but it doesn't.
3 Answers
Steven Parker
231,269 PointsI tried this in the workspace and it seems to run as I would expect:
How many tickets would you like to buy, Joe? blue
Oh no! We ran into an issue. invalid literal for int() with base 10: 'blue'. Please try again...
The "Oh no..." part clearly indicates the ValueError exception was caught, and the inserted message indicates the cause. If I type the letter 'e' instead of the word "blue" I'll get the same inserted message as you saw.
Mathew V L
2,910 PointsSteven Parker Is that really expected? The ". invalid literal for int() with base 10: 'blue'. Please try again..." should run the same as if we were inputting 1k tickets correct? When I type in 1000 which is a ValueError, I get "Oh no, we ran into an issue. There are only 100 tickets remaining. please try again!!!! ."
Kind of confused but any help would be appreciated!
Mathew V L
2,910 PointsI looked at another thread and found this:
Hey! I had the same issue so I started to google it and try to change my code. The thing I realized that an error occurs when we want a character to be an integer. But it's not true and we have no exception for it (I dont't know why as it's ValueError).
And after a long time i found the solution:
try:
number_tickets = int(number_tickets)
if number_tickets > tickets_remaining:
raise ValueError
except ValueError as err:
print("Try again. We have only {} tickets.".format(tickets_remaining))
Definitely resolved the issue, but not sure it's what we want
Steven Parker
231,269 PointsTyping 1000 would not generate a value error, but you raise one explicitly:
if number_of_tickets > tickets_remaining:
raise ValueError("There are only {} tickets remaining".format(tickets_remaining))
And the message shown is the one you passed to the "raise" function.
So this is also exactly the result for what is programmed. I suppose the real issue is what do you want it to do?
Mathew V L
2,910 PointsHi, Thanks Steven Parker!! for the help. from the video, the teacher says we want to make all errors understandable. So when we tried to use a string in "How many tickets?" I wasn't expecting invalid literal, I expected it to show "Oh no! We ran into an issue. There are only {} tickets remaining". tickets_remaining. Please try again.
To simply put it, how raise an error to output something else besides "invalid literal for int() with base 10"
Eddie Licea
1,610 PointsThat's exactly what I wanted to know lol.