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Python Python Collections (2016, retired 2019) Lists Disemvowel

Posted by Adrian Brenton
Adrian Brenton
8,110 Points

Having trouble with my understanding and solving this challenge - help is much appreciated!

Hello everyone,

I've been trying to solve this problem for some time now, and have had no success so far.

I'm concerned that my logic is flawed somewhere, and I can't identify what I'm missing here.

I've attached my latest attempt at coding a solution, and some advice in where my thinking needs adjustment would be much appreciated, as I'd like to be able to figure out a solution for this challenge.

Many Thanks in advance!

Kind Regards

disemvowel.py 
def disemvowel(word):
    vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]

    disemvoweled_word = []

    for letter in word:
        if letter not in vowels:
            disemvoweled_word.append(letter)
            return disemvoweled_word
        else:
            break

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,423 Points
Chris Freeman
Chris Freeman
Treehouse Moderator 68,423 Points

You headed in the correct direction!

  • if a non-vowel is the first character, the else/break causes the loop to end result in a default return None. :point_right: remove the else/break
  • if a vowel is the first character, it is appended to disemvoweled_word then returned immediately. :point_right: move the return statement outside of for loop
  • the expected return object should be a string. :point_right: use "".join() on disemvoweled_word to get a string

Post back if you need more help. Good luck!!!

Adrian Brenton
Adrian Brenton
8,110 Points

Thank you for your assistance Chris!