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![Carl Smith](https://uploads.teamtreehouse.com/production/profile-photos/5714272/micro_IMG_0966.jpg)
Carl Smith
8,185 PointsHaving trouble with this program
Not sure what I'm doing wrong here, just getting a "Bummer, tray again" error.
def parse_answer(answer, kind="string")
print answer + " "
answer = gets.chomp
answer = answer.to_i if kind == "number"
return answer
end
1 Answer
![Carlos Federico Puebla Larregle](https://uploads.teamtreehouse.com/production/profile-photos/5116222/micro_1011735_10201788726664507_1068010854_n.jpg)
Carlos Federico Puebla Larregle
21,074 PointsYou have to check if the "kind" variable is a number before you convert the "answer" variable to an integer, you could do it, like this:
def parse_answer(answer, kind="string")
if kind == "number"
answer = answer.to_i
end
return answer
end
I hope that helps a little bit.
Carl Smith
8,185 PointsCarl Smith
8,185 PointsThank you, I was a little confused on the way to do it. I tried copying what was done in the video before this. Was unclear on how to perform. this clears it up. Thank you again!