Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Ruby Ruby Loops Build a Simple Contact List Methods That Return a Value

Posted by Carl Smith
Carl Smith
8,185 Points

Having trouble with this program

Not sure what I'm doing wrong here, just getting a "Bummer, tray again" error.

ask.rb 
def parse_answer(answer, kind="string")
  print answer + " "
  answer = gets.chomp
  answer = answer.to_i if kind == "number"
  return answer
end

1 Answer

Carlos Federico Puebla Larregle
Carlos Federico Puebla Larregle
21,073 Points
Carlos Federico Puebla Larregle
Carlos Federico Puebla Larregle
21,073 Points

You have to check if the "kind" variable is a number before you convert the "answer" variable to an integer, you could do it, like this:

def parse_answer(answer, kind="string")
  if kind == "number"
    answer = answer.to_i
  end
  return answer
end

I hope that helps a little bit.

Carl Smith
Carl Smith
8,185 Points

Thank you, I was a little confused on the way to do it. I tried copying what was done in the video before this. Was unclear on how to perform. this clears it up. Thank you again!