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# having trouble with this question ,any ideas ?!

The method below checks the speed of a car and returns a string value: either "safe" or "unsafe". Return "safe" if: The car_speed passed in as an argument is greater than or equal to the number 40. The car_speed passed in as an argument is less than or equal to the number 50. Otherwise, return "unsafe". Hint: You should use the && logical operator to accomplish this task. :)

ruby.rb
```def check_speed(car_speed)
car_speed = gets.chomp.to_i
if ( car_speed >= 40 ) && ( car_speed <= 50 )
puts "safe"
end
else
puts "unsafe"
end
```

Use another if statement instead of an else, if you are using else, it counts as the end of the first if.

def check_speed(car_speed) print "what is your speed?" car_speed = gets.chomp.to_i if ( car_speed >= 40 ) && ( car_speed <= 50 ) puts "safe" if ( car_speed <= 50 ) && ( car_speed >= 40 ) puts "unsafe" end

Sorry I have no idea what I was thinking, try putting return instead of puts.

Oh just seen that you put an end after the first 'if' should probably look like : ```def check_speed(car_speed) # write your code here print "what is your speed?" car_speed = gets.chomp.to_i if ( car_speed >= 40 ) && ( car_speed <= 50 ) return "safe" else return "unsafe" end```

def check_speed(car_speed) print "what is your speed?" car_speed = gets.chomp.to_i if (car_speed >= 40) && (car_speed <= 50) puts "safe" elsif (car_speed < 40) && (car_speed > 50) puts "unsafe" end end

for some reasons doesn't work. Could you help, please

Use return instead of puts as you are returning the final value to the function rather then displaying it.