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Start your free trialneftali mendomo
1,364 Pointshello! I have an issue on how to find the requested value on question three. I multiplied 1.6 by the 20.
In the "style.css", they ask me to find the unit-less value of the" line-height" multiplying 1.6 font-size value (which is 20 ). I do so, and find 32 , but the answer is still not accepted. Please help me to see what I did wrong.
<!DOCTYPE html>
<html>
<head>
<title>Lake Tahoe</title>
<link rel="stylesheet" href="page.css">
<link rel="stylesheet" href="style.css">
</head>
<body>
<header id="top" class="main-header">
<span class="title">Journey Through the Sierra Nevada Mountains</span>
<h1>Lake Tahoe, California</h1>
</header>
<div class="primary-content t-border">
<p class="intro">
Lake Tahoe is one of the most <span>breathtaking attractions</span> located in California. It's home to a number of ski resorts, summer outdoor recreation, and tourist attractions. Snow and skiing are a significant part of the area's reputation.
</p>
<a href="#more">Find out more</a>
</div>
<footer class="main-footer">
<p>All rights reserved to the state of <a href="#">California</a>.</p>
<a href="#top">Back to top »</a>
</footer>
</body>
</html>
/* Complete the challenge by writing CSS below */
.intro{
font-size:1.25em;
line-height:32;
}
3 Answers
Steven Parker
231,269 PointsThis is a bit of a "trick question". Since a unitless line-height is taken as a multiplier, the value you would use to make the height 1.6 times larger than the font-size is ... yep ... 1.6.
KRIS NIKOLAISEN
54,971 PointsThe line-height is the multiplier. You don't need to do multiplication yourself.
.intro{
font-size:1.25em;
line-height: 1.6;
}
neftali mendomo
1,364 Pointsthank you. bellow beginner level.
Steven Parker
231,269 Pointsneftali mendomo โ Glad to help. You can mark a question solved by choosing a "best answer".
And happy coding!