Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialGeorge Lugo
Python Web Development Techdegree Student 922 PointsHello I would like to see what I am doing wrong in the problem below
template = "Hi, I'm {name} and I love to eat {food}!"
def string_factory(name = None, food= None): if name and food: print template.format(name="kenneth", food= "tacos") else: print(Hi no name!")
# Example:
# values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"}]
# string_factory(values)
# ["Hi, I'm Michelangelo and I love to eat PIZZA!", "Hi, I'm Garfield and I love to eat lasagna!"]
template = "Hi, I'm {name} and I love to eat {food}!"
def string_factory(name = None, food= None):
if name and food:
print template.format(name="kenneth", food= "tacos")
else:
print(Hi no name!")
1 Answer
Steven Parker
231,269 PointsLet's take another look at the instructions.
The challenge asked you to: "Write a function named string_factory that accepts a list of dictionaries as an argument. Return a new list of strings...". You did correctly name the function string_factory. But:
- instead of a list of dictionaries, your function accepts a name and a food as arguments
- instead of a new list of strings, your function does not return anything
- your function prints but no printing was called for
- you'll probably need a loop to process each item in the incoming list
- you're missing an open quote on the last line (but you probably don't need that entire line)