Hello. Im totally confused about this index position.Can anyone help?

Yes, I totally remember having that confusion too when I started :)

One way to look at it is this: OK, let's try both ways and see the difference, and there you will see what each one does.

Try this on your browser's dev tools (in the Console tab):

**** NOTE: **** You will need to be very careful with the syntax (every semicolon, bracket, etc. is important, otherwise you'll just receive errors and errors)

var students = ['sasha', 'lynn', 'jenifer', 'paul'];
for(var i = 0; i<students.length; i+=1) {
    console.log(students[i]);
}
// This will output: 
// sasha
// lynn
// jenifer
// paul

Now, try this:

var students = ['sasha', 'lynn', 'jenifer', 'paul'];
for(var i = 0; i<students.length; i+=1) {
    console.log(students[0]);
}
// This will output: 
// sasha (and then a four somewhere aside)

What that four aside means is that sasha was printed four times.

Summary:

• The index 0 will always be the first one in the array, no matter how many times you loop.
• The index i will increase by one every time, and then it will be one time each item in the array (first it will represent the item 0, then the item 1 and so on until the end you set for the loop).

'i' represents the index value of each item in an array. Since an array is zero-indexed, you store the numeric value of 0(zero) when declaring the variable 'i' in the for loop(var i = 0). Keep in mind that the value of the variable 'i' will increase by 1 every time the loop runs(i +=1) till it is just below the length property of the given array(i < students.length). So 'i' will be 0, 1, 2 and finally 3 i.e. students[0], students[1], students[2] and students[3], logging each iteration in the console of the browser.