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JavaScript JavaScript Loops, Arrays and Objects Simplify Repetitive Tasks with Loops Refactor Using a Loop

Posted by Juan Gaitan V.
Juan Gaitan V.
7,441 Points

Hello, my code isn't running, though I believe it prints what you ask.

What do you think?

script.js 
for (x = 0; x <= 24; ) {
  console.log(++x % 2? '' : x);
}
index.html 
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>JavaScript Loops</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

1 Answer

Trevor Skelton
Trevor Skelton
1,101 Points
Trevor Skelton
Trevor Skelton
1,101 Points

A for loop requires the structure "for( initialize counter variable; when to stop counting; increment counter variable)". You can use the counter variable in your code inside the for loop. Switch your variable around and match the structure I described, e.g. for(int i=0;i<5;i++) { echo i; }. Also, you don't need all of the logic in the log statement. Think of a way to use your counter variable to go through just even numbers and just log(i).

Juan Gaitan V.
Juan Gaitan V.
7,441 Points

you mean...

for (x = 1; x <= 24; x ++) {
  console.log(x % 2? '' : x);
}
Trevor Skelton
Trevor Skelton
1,101 Points
Trevor Skelton
Trevor Skelton
1,101 Points

So now you have the syntax right. Your expression in the log parameter is correct, but I don't know if you can pass in an expression. Just do console.log(x). Think of a way to use your x as counting every even number in your for loop header. In other words, right now it is counting by adding 1 every time. What could you make it do instead of increment by one?