Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

iOS Swift Functions and Optionals Optionals Review: Functions

help

what is the correct answer ?

divisible.swift
func isDivisible(#dividend: Int, #divisor: Int) -> Bool {
    if dividend % divisor == 0 {
        return true
    } else {
        return false
    }
}

2 Answers

Holger Liesegang
Holger Liesegang
50,595 Points

Hi Zeyad!

This challenge asks you for the opposite of the isDivisible function - so instead of looking for a truthy value you have to look for the falsy one like this:

func isNotDivisible(#dividend: Int, #divisor: Int) -> Bool {
  if dividend % divisor != 0 {
    return true
  } else {
    return false
  }
}

Hi there,

Another solution to this is to use the existing method and negate its returned value:

func isNotDivisible(#dividend: Int, #divisor: Int) -> Bool {
   return !isDivisible(dividend: dividend, divisor: divisor)
}

Steve.