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# Help !

Help !

while_loops.swift
```let numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
```

Hi Yasser,

In this challenge, you have an array and the question wants you to print out every element in the array using a `while` loop.

We need to print out each number in the array using a while loop and the println statement. A while loop continues to loop while a condition is, or is not, met. In this example, the end point would be reached when we've printed out every number in the array. That number can be found using the `count` property of the array. We start at the first position, which is element zero and print out all elements up to the last one. We can access each element with square brackets, `numbers[0]`, then `numbers[1]` etc. This means we need a number that counts from zero and stops before `numbers.count`, so we need to create an index variable to do that. Start that index at zero, print out `numbers[index]` then increment `index`. Keep doing this while `index` is less than `numbers.count`.

One solution could look like this:

```let numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
var index = 0;  // start counting from zero
while (index < numbers.count){ // stop if index isn't < count
println(numbers[index])  // print the index element
index++ // increment index
}
```

I hope that helps,

Steve.