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SAIADITHYA CUMBULAM
688 Pointshelp
def loopy(items): for num in items: if items.index[0] is 'a': continue print(num)
def loopy(items):
for num in items:
if items.index[0] is 'a':
continue
print(num)
2 Answers
Mark Ihrig
19,966 PointsYour code is the following:
def loopy(items):
for num in items:
if items.index[0] is 'a':
continue
print(num)
Your third line in your code has if items.index[0] is 'a': You have "items", and it should be "num". You don't need to use the word .index, the brackets with zero inside is all that is needed. The square brackets are the indexing operator. num[0] returns the first item in the array num. The word "is" will work for the quiz, but I have seen others use "==" instead. The word "is" will return True if two variables point to the same object, == if the objects referred to by the variables are equal. Both of the codes below will work for this quiz.
def loopy(items):
for num in items:
if num[0] is 'a':
continue
print(num)
or
def loopy(items):
for num in items:
if num[0] == 'a':
continue
print(num)
SAIADITHYA CUMBULAM
688 PointsThank you so much :)
Mark Ihrig
19,966 PointsYou are welcome!
Chris Freeman
Treehouse Moderator 68,423 PointsChris Freeman
Treehouse Moderator 68,423 PointsIn this case, using
==is preferred.isshould be used when comparing if two objects are literally the same object in memory.