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Android Build a Blog Reader Android App Using Intents to Display and Share Posts Easy Sharing with Intents

Javier Briones
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Javier Briones
Front End Web Development Techdegree Student 29,674 Points
Posted by Javier Briones
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Javier Briones
Front End Web Development Techdegree Student 29,674 Points

Help

I can't figure what's wrong with my solution. Here's my code

if(itemId == R.id.action_share)  
{
    // Add code here!
    Intent shareIntent = new Intent(Intent.ACTION_SEND);
    shareIntent.setType("text/plain");
    String Hello = "Hello";
    shareIntent.putExtra(Intent.EXTRA_TEXT, Hello);
    startActivity(Intent.createChooser(shareIntent, R.string.chooser_title));
}

And here's the error I get:

JavaTester.java:58: cannot find symbol
symbol  : method createChooser(android.content.Intent,int)
location: class android.content.Intent
    startActivity(Intent.createChooser(shareIntent, R.string.chooser_title));
                        ^
1 error

I still don't understand what is wrong with my code

2 Answers

Ben Jakuben
STAFF
Ben Jakuben
Treehouse Teacher
Ben Jakuben
Ben Jakuben
Treehouse Teacher

You need to pass in an actual String as the 2nd parameter, not just the string ID:

startActivity(Intent.createChooser(shareIntent, getString(R.string.chooser_title)));

It's not totally clear, but the error message helps track this down:

symbol : method createChooser(android.content.Intent,int)

It's saying that it can't find a createChooser() method that has an "int" as the 2nd parameter.