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C# C# Objects Loops and Final Touches For Loops

Help - Error with Frog/Loop Challenge code

I am getting the following error and I can't figure out why: FrogStats.cs(21,17): error CS0019: Operator +=' cannot be applied to operands of typedouble' and `Treehouse.CodeChallenges.Frog' Compilation failed: 1 error(s), 0 warnings

Code:

namespace Treehouse.CodeChallenges { class FrogStats { private readonly Frog _tongueLength;

    public FrogStats(Frog tongueLength)
    {
        _tongueLength = tongueLength;
    }

    public static double GetAverageTongueLength(Frog[] frogs)
    {
        double sum = 0;
        double tally = 0;
        double average = 0;

        for(int i = 0; i < frogs.Length; i++)
        {
            Frog frog = frogs[i];
            sum += frog;

            i++;
        }

        average = sum / frogs.Length - 1;
        return average;
    }
}

}

FrogStats.cs
namespace Treehouse.CodeChallenges
{
    class FrogStats
    {
        private readonly Frog _tongueLength;

        public FrogStats(Frog tongueLength)
        {
            _tongueLength = tongueLength;
        }

        public static double GetAverageTongueLength(Frog[] frogs)
        {
            double sum = 0;
            double tally = 0;
            double average = 0;

            for(int i = 0; i < frogs.Length; i++)
            {
                Frog frog = frogs[i];
                sum += frog;

                i++;
            }

            average = sum / frogs.Length-1;
            return average;
        }
    }
}
Frog.cs
namespace Treehouse.CodeChallenges
{
    public class Frog
    {
        public int TongueLength { get; }

        public Frog(int tongueLength)
        {
            TongueLength = tongueLength;
        }
    }
}

2 Answers

Steven Parker
Steven Parker
216,135 Points

You can't add a "frog" to a number. You probably only wanted to add the frog's tongue length.

Also, you have an increment clause in your "for" loop, but also a separate increment statement inside the loop (you probably don't want both). And why would you subtract one from the average?

Steven, Thank you! That helped. I figured it out.