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Ping Li2,689 Points
Help! How do you do this challenge?
My loopy function needs to skip an item this time, though. Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member. Example: ["abc", "xyz"] will just print "xyz".
def loopy(items): # Code goes here for things in items: if things.index("a") = 0: continue else: print(things)
Chris FreemanTreehouse Moderator 68,154 Points
Here are the steps:
- Iterate over each
item in itemsusing
- check if first character of each item is an "a"
- if not, print item
Post back if you need more help. Good luck!