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Python Python Basics (2015) Shopping List App Continue

Ping Li
Ping Li
2,689 Points

Help! How do you do this challenge?

My loopy function needs to skip an item this time, though. Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member. Example: ["abc", "xyz"] will just print "xyz".

breaks.py
def loopy(items):
    # Code goes here
    for things in items:
        if things.index("a") = 0:
            continue
        else:
            print(things)

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,154 Points

Here are the steps:

  • Iterate over each item in items using for loop
  • check if first character of each item is an "a"
  • if not, print item

Post back if you need more help. Good luck!

Ping Li
Ping Li
2,689 Points

How do you check if first character of each item is an "a"?

Chris Freeman
Chris Freeman
Treehouse Moderator 68,154 Points

In a loop of item in items, the test would be:

item[0] == "a"

Ping Li
Ping Li
2,689 Points

This code:

def loopy(items):
    # Code goes here
    for item in items:
        if item[0] = "a":
            continue
        else:
            print(item)

is still not working.

Chris Freeman
Chris Freeman
Treehouse Moderator 68,154 Points

Be sure to use a comparison ==, and not an assignment = operator