Help in resolving a Challenge Task

Hi,

Could you please let me know what is wrong and what Am I missing as the out put give me correct when checked in python Idle but here in the site displays "Bummer! Didn't get the right count for some of the words."

Create a function named word_count() that takes a string. Return a dictionary with each word in the string as the key and the number of times it appears as the value.

Here is my program:

def word_count(str1): str1_list = str1.lower().split() str1_dict = {} for word in str1_list: count = 1 if word in str1_dict: count += 1 str1_dict[word] = count else: count = 1 str1_dict[word] = count return str1_dict

Below is the sample output I got when checked in python idle

str1 = 'siva krishna raju vegesina raju rama reddy vegesina krishna siva yadav mujeeb john sameer'

word_count(str1) {'vegesina': 2, 'mujeeb': 1, 'reddy': 1, 'siva': 2, 'john': 1, 'rama': 1, 'yadav': 1, 'krishna': 2, 'sameer': 1, 'raju': 2}

# E.g. word_count("I am that I am") gets back a dictionary like:
# {'i': 2, 'am': 2, 'that': 1}
# Lowercase the string to make it easier.
# Using .split() on the sentence will give you a list of words.
# In a for loop of that list, you'll have a word that you can
# check for inclusion in the dict (with "if word in dict"-style syntax).
# Or add it to the dict with something like word_dict[word] = 1.

def word_count(str1):
    str1_list = str1.lower().split()
    str1_dict = {}
    for word in str1_list:
        count = 1
        if word in str1_dict:
            count += 1
            str1_dict[word] = count
        else:
            count = 1
            str1_dict[word] = count
    return str1_dict