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Java Java Objects (Retired) Delivering the MVP Defaulting Parameters

Ronit Mankad
Ronit Mankad
12,166 Points

Help!. Logical error

This is a little hard for me. Please help.

public class Example {

  public static void main(String[] args) {
    ShoppingCart cart = new ShoppingCart();
    Product pez = new Product("Cherry PEZ refill (12 pieces)");
    cart.addItem(pez, 5);
    /* Since a quantity of 1 is such a common argument when adding a product to the cart,
     * your fellow developers have asked you to make the following code work, as well as keeping
     * the ability to add a product and a quantity.
    Product dispenser = new Product("Yoda PEZ dispenser");
    /* Uncomment the line following this comment,
       after adding a new method using method signatures,
       to solve their request in ShoppingCart.java

public class ShoppingCart {

  public void addItem(Product item) {
    String ch=console.readLine("Do you want more than 1 piece?. Press 'Y' for yes and 'N' for no\n");
    if(ch.equals('Y')) {
    int quantity=System.getLine("How many items do you want?");
    System.out.printf("Adding %d of %s to the cart.%n", quantity, item.getName());
    /* Other code omitted for clarity. Please imagine
       lots and lots of code here. Don't repeat it. 
  }else {
      System.out.printf("Adding 1 of %s to your cart\n",item.getName());

public class Product {
  /* Other code omitted for clarity, but you could imagine
     it would store price, options like size and color
  private String mName;

  public Product(String name) {
      mName = name;

  public String getName() {
      return mName;

1 Answer

anil rahman
anil rahman
7,786 Points

Hi all i did was this:

public void addItem(Product item) { //make new method but ignoring adding a quantity just add item
    System.out.printf("Adding %d of %s to the cart.%n", 1, item.getName()); 
//now instead of saying adding quantity it says adding 1

Ronit Mankad
Ronit Mankad
12,166 Points

Thank you...making another method with just the item works!