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10,042 Pointshelp me
<?php
class Render{
public static function listIngredients($ingredients)
{
$output = ""; -----> why did you put?
foreach ($ingredients as $ing){
$output.= $ing["amount"]." ". $ing["measure"]. " " .$ing["item"];
$output.="\n";
}
}
public static function displayRecipe($recipe)
{
$output=""; -----> why did you put?
$output .= $recipe ->getTitle() . " by " . $recipe -> getSource();
$output .="\n";
$output .=implode(", ",$recipe->getTags());
$output .="\n\n";
$output .=self::listingredients($recipe->getIngredients());------------> help me self?????
$output .="\n";
$output .=implode("\n", $recipe->getInstruction());
$output .="\n";
$output .= $recipe->getYield();
}
}
?>
2 Answers
Walter Allen
iOS Development with Swift Techdegree Student 16,023 PointsI believe you are asking the reasoning behind the
$output = "";
instruction. Is that correct?
If so, what you are doing is initializing the $output variable to the empty string so that you can then concatenate each string you pull from the array in the loop to the string. If you were to initialize the $output variable within the string, it would only be available within the scope of the for statement, and you wouldn't be able to print the completed output string to the console after the for loop is completed running.
Does that make sense? (If not, let me know, and I'll try to answer it again in a different way. If that's not what you were asking, clarify your question, and I'll try again. :))
Trần Phúc
2,264 PointsYou must define variable before you concatenate it
jinhwa yoo
10,042 Pointsjinhwa yoo
10,042 Pointspublic function __toString(){
$output ="You are calling a " . CLASS. "object with the title \""; $output .= $this ->getTitle(). "\""; $output .= "\nIt is stored in ". basename(FILE) . "at" .DIR . "."; $output .="\nThis display is from line ". LINE . "in method" . METHOD; return $output; } ???why put _tostring()???