Ruby Ruby Loops Ruby Loops The Ruby Loop

shree sri
shree sri
540 Points
Posted by shree sri
shree sri
540 Points

help me to resolve

def repeat(string, times) fail "times must be 1 or more" if times < 1 counter = 0 loop do string = "shree" puts string if counter == 1 break end end end

loop.rb 
def repeat(string, times)
  fail "times must be 1 or more" if times < 1
  counter = 0
  loop do
    string = "shree"
    puts string
    if counter == 1 
    break
    end
  end
end

2 Answers

Elian Kloppenburg
Elian Kloppenburg
22,903 Points
Elian Kloppenburg
Elian Kloppenburg
22,903 Points

Hi Shree,

Couple of things wrong:

  • You are not printing
  • You are inputting an incorrect string
  • You are not incrementing counter, so it will stay 0 forever
  • You are not comparing counter with times ( both vars ) to break out of the loop

Try your code like this

def repeat(string, times)
  fail "times must be 1 or more" if times < 1
  counter = 0
  loop do
    print string
    counter += 1
    if counter == times
      break    
    end
  end
end
andynguyen9
andynguyen9
1,629 Points
andynguyen9
andynguyen9
1,629 Points

Why there are 3 ends?

What is "fail" here? Search the net revealed that it is a Kernel method like puts=> don't understand.

fail "times must be 1 or more" if times < 1 => don't understand.

Thank you.