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Start your free trialIdan shami
13,251 Pointshelp me understand something... task 3 teacher stats
hi (: I am having some problems with this task.... when I am trying the code in work spaces it gives me 5 lists and not all of the values in 1 list, so I tried looking at others answer and I found this one
def courses(a_dict):
course_list = []
for teachers in a_dict:
for courses in a_dict[teachers]:
course_list.append(courses)
return course_list
why is he using 2 loops? and what a_dict[teacher] does that affect the list to be 1...? can I do it with the .value() statement?
I really appreciate your help! thanks!
Idan.
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
teachers_course = {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],'KennethLove': ['Python Basics', 'Python Collections']}
def num_teachers(teachers_course):
count = 0
for teacher in teachers_course:
if teacher in teachers_course:
count += 1
else:
count = 0
return count
def num_courses(teachers_course):
count_course = 0
for course in teachers_course.values():
if course in teachers_course.values():
count_course += len(course)
else:
count_course = 0
return count_course
def courses(teachers_course):
values_list = []
for value in teachers_course.values():
values_list.append(value)
return values_list
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
teachers_course = {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],'KennethLove': ['Python Basics', 'Python Collections']}
def num_teachers(teachers_course):
count = 0
for teacher in teachers_course:
if teacher in teachers_course:
count += 1
else:
count = 0
return count
def num_courses(teachers_course):
count_course = 0
for course in teachers_course.values():
if course in teachers_course.values():
count_course += len(course)
else:
count_course = 0
return count_course
def courses(teachers_course):
values_list = []
for value in teachers_course.values():
values_list.append(value)
return values_list
1 Answer
Chris Freeman
Treehouse Moderator 68,453 PointsIn your attached code snippet:
def courses(a_dict):
course_list = []
for teachers in a_dict: # <-- teacher is each key in a_dict
for courses in a_dict[teachers]: # <-- a_dict[teachers] will be the list of courses
# courses will be each course in the list of courses
course_list.append(courses) # <-- append course to course_list
return course_list
But, since a_dict[teachers]
is a list already, it can be added to the courses_list
directly and skip the inner for loop with
course_list.extend(a_dict[teachers])
Your posted code, is very close to the solution!
def courses(teachers_course):
values_list = []
for value in teachers_course.values():
values_list.append(value) # <-- use extend instead of append otherwise you'll get a list of list
return values_list # <-- return value indented too far
Post back if you need more help. Good luck!!