Help me understand this closure logic

Question

I'm reviewing some of the materials outlining closures and there is one part of the logic that seems backwards to me. My last line of code reads displayString(printString) and prints the following:

Printing the string passed in: I'm a function inside another function

From what I understand the printString function stores the displayString's string as aString.

it would at least seem more logical that if you're passing printString to displayString that it would print whatever is in the printString function before the displayString function.

Can anyone elaborate ?

// This function takes a string and prints it
func printString (aString: String) {
    println("Printing the string passed in: \(aString)")
}



func displayString(printStringFunc: (String) -> Void) {
    printStringFunc("I'm a function inside another function")
}


displayString(printString)

Answer 1 · 2015-07-15T03:51:05Z

July 15, 2015 3:51am

// I found the logic really hard to follow with the above example.
// To sum it up, we can pass functions as parameters.
// It might make more sense when using numbers.
func addOneToNumber (number: Int) -> Int {
    return number + 1
}


// This is a function, that takes another function, 
// a function of type "(Int) -> (Int)"
// that is passed in as a parameter 
// and returns an Int.


func addTwoToYourOtherFunction (takeAFunctionAndAddTwo: (Int) -> Int) -> Int {

    return takeAFunctionAndAddTwo(2)
// takes the function you passed in and passes 2 as a parameter to it.
}




// Now take the above function and pass another function of the specified type 
//" (Int) -> (Int) " as a  parameter.

addTwoToYourOtherFunction(addOneToNumber)   // 3

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Bryan Elliott

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Help me understand this closure logic

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Chris Stromberg

Chris Stromberg