Get this bummer: Didn't get an exit from 'start_movie' What?
import sys start = input("Do you want to start the movie? ") if start != "N" or start != "n": print("Enjoy the show!") else: sys.exit()
Jennifer NordellTreehouse Staff
Hi there! You're close... really close. You are off by one word. You used the word
or, but you need the word
Let's take a look at your logic for a minute. Remember, for an expression in an
or statement only one has to be true for the entire thing to be true. So if we were to send in "N", what happens? It asks if "N" is not equal to "N". That evaluates to false so it moves to the next part of the
or statement. It then asks if "N" is not equal to "n". It is not so this evaluates to true which means that the "Enjoy the show!" prints. This is obviously not what was intended.
The same thing is true for the "n". It first asks if "n" is not equal to "N". This evaluates to true and the next condition is never even checked. It goes directly to printing "Enjoy the show!".
Instead, we need to say that if the answer was both not equal to "N" and not equal to "n", then exit. As your code is currently, there is nothing the user can type which results in the
else statement being reached.
Hope this helps!
Ben Reynolds35,167 Points
In your if statement, both of the conditions need to be checked so use "and" instead of "or".
In fact I'd go one further and simplify it like this:
if start.lower() != "n"
Then you don't need to do two checks at all. I can see why it was confusing though, that is a weird error message. It implies you have to name something "start_movie" but that's not actually a requirement, you could name your input variable whatever you want.