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Julian Jimenez
7,229 PointsHelp please, I don't understand where I'm going wrong.
def word_count(string): string = string.lower() words = string.split(" ") my_dict = {} for word in words: num = words.count(word) my_dict[word] = num return my_dict
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(string):
string = string.lower()
words = string.split(" ")
my_dict = {}
for word in words:
num = words.count(word)
my_dict[word] = num
return my_dict
4 Answers

Jennifer Nordell
Treehouse TeacherHi there! You're actually doing really well here! You are very very close. It wants you to split on all whitespace. This includes tabs etc. But you are splitting only on spaces. To split on all whitespace use the split method with no parameters like this: split()
. So, if I erase the " " inside the parentheses your code passes!
Hope this helps!

Alexander Davison
65,454 PointsYour program is only splitting by spaces.
The challenge wants you to split on all whitespace.
.split(" ")
splits on only spaces, but .split()
(which the challenge is expecting) splits on all whitespace, not only spaces. Whitespace includes spaces, tabs, newlines, etc.
I hope this helps
Happy coding!
~Alex

james south
Front End Web Development Techdegree Graduate 33,258 Pointstry changing the split delimiter to () to split on more than just a space(' ')

Julian Jimenez
7,229 PointsThanks guys!, it works now :D
Alexander Davison
65,454 PointsAlexander Davison
65,454 PointsDarn! Answered at the same time xD