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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by Julian Jimenez
Julian Jimenez
7,229 Points

Help please, I don't understand where I'm going wrong.

def word_count(string): string = string.lower() words = string.split(" ") my_dict = {} for word in words: num = words.count(word) my_dict[word] = num return my_dict

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(string):
    string = string.lower()
    words = string.split(" ")
    my_dict = {}
    for word in words:
        num = words.count(word)
        my_dict[word] = num
    return my_dict

4 Answers

Jennifer Nordell
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STAFF
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher
Jennifer Nordell
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there! You're actually doing really well here! You are very very close. It wants you to split on all whitespace. This includes tabs etc. But you are splitting only on spaces. To split on all whitespace use the split method with no parameters like this: split(). So, if I erase the " " inside the parentheses your code passes!

Hope this helps! :sparkles:

Alexander Davison
Alexander Davison
65,469 Points

Darn! Answered at the same time xD

Alexander Davison
Alexander Davison
65,469 Points
Alexander Davison
Alexander Davison
65,469 Points

Your program is only splitting by spaces.

The challenge wants you to split on all whitespace.

.split(" ") splits on only spaces, but .split() (which the challenge is expecting) splits on all whitespace, not only spaces. Whitespace includes spaces, tabs, newlines, etc.

I hope this helps :grin:

Happy coding! :tada:

:dizzy: ~Alex :dizzy:

Julian Jimenez
Julian Jimenez
7,229 Points
Julian Jimenez
Julian Jimenez
7,229 Points

Thanks guys!, it works now :D