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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Help please, I don't understand where I'm going wrong.

def word_count(string): string = string.lower() words = string.split(" ") my_dict = {} for word in words: num = words.count(word) my_dict[word] = num return my_dict

wordcount.py
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(string):
    string = string.lower()
    words = string.split(" ")
    my_dict = {}
    for word in words:
        num = words.count(word)
        my_dict[word] = num
    return my_dict    

4 Answers

Jennifer Nordell
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there! You're actually doing really well here! You are very very close. It wants you to split on all whitespace. This includes tabs etc. But you are splitting only on spaces. To split on all whitespace use the split method with no parameters like this: split(). So, if I erase the " " inside the parentheses your code passes!

Hope this helps! :sparkles:

Darn! Answered at the same time xD

Your program is only splitting by spaces.

The challenge wants you to split on all whitespace.

.split(" ") splits on only spaces, but .split() (which the challenge is expecting) splits on all whitespace, not only spaces. Whitespace includes spaces, tabs, newlines, etc.

I hope this helps :grin:

Happy coding! :tada:

:dizzy: ~Alex :dizzy:

Thanks guys!, it works now :D