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Java Java Basics Getting Started with Java Strings, Variables, and Formatting

Posted by a p
.a{fill-rule:evenodd;}techdegree
a p
Python Web Development Techdegree Student 2,362 Points

Help Required Please!!!!!! as far as i can tell I am coding it right. Help please

is this a bug or am i missing something here???????

Name.java 
// I have setup a java.io.Console object for you named console
String firstName = "Andy";
console.printf ("%s can code in Java", firstName);

2 Answers

srikarvedantam
srikarvedantam
8,369 Points

Well, you are missing a '!' at the end of the console.printf's format string. Here's a solution:

String firstName = "Srikar";
console.printf("%s can code in Java!", firstName);
a p
.a{fill-rule:evenodd;}techdegree
a p
Python Web Development Techdegree Student 2,362 Points

thanks for the quick reply. have just worked that out after having to go back and redo it for about the 5th time. the thing that threw me was that i had missed the "!" on task 2 and it passed it.

a p
.a{fill-rule:evenodd;}techdegree
a p
Python Web Development Techdegree Student 2,362 Points

thank you

srikarvedantam
srikarvedantam
8,369 Points

Welcome, Andy.

a p
.a{fill-rule:evenodd;}techdegree
a p
Python Web Development Techdegree Student 2,362 Points

you are all right about the space after printf aswell.

have just redone task 2 again with both a space after printf and no "!" and it still passes.

It is no wonder i was struggling with it......

Anyway Thank you to you all, as you were all right...

Anjali Pasupathy
Anjali Pasupathy
28,883 Points
Anjali Pasupathy
Anjali Pasupathy
28,883 Points

You've nearly got it. You just need to get rid of the space right after "printf".

console.printf("%s can code in Java", firstName);

I hope this helps!