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# Help to solve the code challenge, defining methods

Hello, im having a hard time with the code challenge below. How can i set the value to the "c" and insert it to the sentence? Thanks!!

Challenge Task 1 of 1 In the previous challenge, we wrote a method that returned the remainder of two arguments when divided. That's cool, but it would be nicer if the method returned the remainder in a nice full sentence. Use string interpolation to return the remainder inside the sentence “The remainder of a divided by b is c.” where a is your “a” variable, b is your “b” variable, and c is the value of a % b.

method.rb
def mod(a, b)
puts "The remainder of #{a} divided by #{b} is #{c}."
return a % b
end

mod(10, 2)

Hi there, I think the wording of the problem is tripping you up. Adding "c" into the equation as a variable will not work because you have not assigned it a value yet. The solution is to get rid of the letter "c" altogether and just plug in the value, "a%b" instead.

def mod(a,b)
return "The remainder of #{a} divided by #{b} is #{a%b}."
end

Alternatively, if you really want to use "c" as a variable, assign it the value of a%b before calling "c" in the string.

def mod(a,b)
c = a % b
return "The remainder of #{a} divided by #{b} is #{c}."
end

Try this:

def mod(a, b)
c = a % b
return "The remainder of #{a} divided by #{b} is #{c}."
end

First, you don't need to call the function (in your code). The code challenge does that automatically. Second, the variable c doesn't exist (in your code). Lastly, you don't need to print anything. All you need to do is to return the valid string (in your... OK, I think you know what I'm about to say).

I hope this helps. ~Alex