Help with the tasl 4/7 in the Objects challenge in Wrapping up the project in PHP

Two things:

(1) Remember that number is an attribute of the PalprimeChecker object. You are accessing the property correctly when you set it ...

$checker->number = 17;

... but you are not accessing it correctly when you echo it. It should look like this:

echo "The number " . $checker->number;

(2) isPalprime is a method of the PalprimeChecker object. It's a lot like the Send method in the PHPMailer object we look at in the video. Let me show you some examples of that:

// #1. incorrect
if ($message == Send) {
    echo "Hooray! The message was sent.";
}

// #2. correct
if ($mail->Send()) {
    echo "Hooray! The message was sent.";
}

Your conditional looks like the incorrect example (#1). You want your conditional to look more like the correct example (#2).

Do those two comments help?

Yes, man, they helped me a lot... that object stuff is an other "stuff"..

Thanks!

Hi Randy- I have followed the video and I am still getting an error myself

Message:

It doesn't look like you are calling the isPalprime method on the $checker object. You should be calling that method in a conditional to determine if you should display “is” or “is not” on the page.

<code>

  <?php
          include_once ("class.palprimechecker.php");

          $checker = new palprimechecker ;

          $checker -> number = 17; 

          echo "The number " . $checker->number;

              if ($number -> isPalprime)
                   {
                  echo " is";
                   }
                  else
                   {
                   echo " is not";

                    }

              echo " a palprime.";

         ?>

</code>

Can you offer any assistance

Thanks

D

The line with the problem is this one:

if ($number -> isPalprime)

Two things to note:

• You are referencing a variable called $number here, but you don't have a variable named that anywhere.
• isPalprime is a method of an object, but this looks like a property.

You'll need to change $number to the name of the variable that is the PalprimeChecker object, and you'll need to add some punctuation to the isPalprime reference so that it calls the method.

Do those tips help?

Got it Thanks

<?php
include_once ("class.palprimechecker.php");


$checker = new palprimechecker ;
$checker->number = 17; 

echo "The number " . $checker->number;

if ($checker->isPalprime())
{
    echo " is";
}
else{
    echo " is not";

}

echo " a palprime.";

?>

Very helpful! Thank you!