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Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today. # Help with "Working with Functions" quiz.

Hi

I am working through the quiz, but I am stuck on a particular question, and wondered if someone could walk me through the question? Here is the code:

```\$numbers = array(1,2,3,4);

\$total = count(\$numbers);

\$sum = 0;

\$output = "";

\$i = 0;

foreach(\$numbers as \$number) {

\$i = \$i + 1;

if (\$i < \$total) {

\$sum = \$sum + \$number;

}

}

echo \$sum;
```

I did copy the code in to my editor to get the answer, to then see if I could almost reverse engineer it, but I still can't quiet workout how to get to the value.

Any help on this is much appreciated :)

Thanks This question is asking what the code displays, so we need to take a look and see what is going to be echo-ed. You can see there's only one thing being echo-ed: the value of \$sum at the very end of the code.

The foreach block is where we're going to get our final value for \$sum, so let's determine what the foreach does. Here's the entire foreach:

```foreach(\$numbers as \$number) {
\$i = \$i + 1;
if (\$i < \$total) {
\$sum = \$sum + \$number;
}
}
```

Breaking this down, each time we go through the foreach, \$sum will be equal to the the previous \$sum + the current number from the numbers array. However, we're also using a counter. If the counter (\$i) is less than \$total, we'll do the sum. If it is greater than **or equal to** \$total, we won't.

\$total counts the \$numbers array. \$total equals 4, because there are 4 items in the array. So we will actually go through the if only 3 times. So as we go through the foreach loop, here's what \$sum and \$i will equal:

1. \$i = 0 + 1 = 1; \$sum = 0 + 1 = 1
2. \$i = 1 + 1 = 2; \$sum = 1 + 2 = 3
3. \$i = 2 + 1 = 3; \$sum = 3 + 3 = 6
4. \$i = 3 + 1 = 4; The if containing the sum code won't run this time because \$i = 4 which is not less than \$total (4). So \$sum stays the same: 6.

So when we echo \$sum at the end, it'll display 6!

why does the sum value increase?

Nevermind it just clicked!

Every time the code executes the value of sum changes aka

for the first loop sum = 1 and the second loop sum = 3

Scott James

It was my pleasure...

With respect to your next question,

It's because when you are concatenating the string in this method, you are pre-pending the number (adding it to the beginning of the string)

```\$output = \$number . \$output; (pre-pending)
```

is different than

```\$output = \$output . \$number; (adding it to the end)
```

foreach will loop as many times as there are items in the array (barring anything that would "break" or exit execution of the loop)

however...

When \$i is no longer less than \$total, the condition is no longer able to be met to hit the code inside the "if". For instance, when 2 < 3, the condition (\$var1 < \$var2) is met. if 3 = 3, then \$var1 is no longer less than \$var2, and the condition isn't met. Hi Gordon

That makes sense. Why is it as soon as some one points it out, you think to yourself "of course that's what it means".

Can someone also help me on this quiz question?

<?php

\$numbers = array(1,2,3,4);

\$total = count(\$numbers);

\$sum = 0;

\$output = "";

\$i = 0;

foreach(\$numbers as \$number) {

```\$i = \$i + 1;

if (\$i < \$total) {

\$output = \$number . \$output;

}
```

}

echo \$output;

?>

How does this echo out 321 in that order?

Thanks to everyone for the help :)

No problem. Scott...

here's a little shortcut when concatenating (to the end)

```\$output .= \$number;
```

is the same as

```\$output = \$output . \$number;
```