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Start your free trialBrett McGregor
Courses Plus Student 1,903 PointsHere is my solution to opposite number game. I used a sort of binary search rather than generating random numbers.
import random
import math
def game():
#set number range
lower = 1
upper = 100
# track number of attempts
attempts = 0
#Introduction message describing the game
print("Hi. I am your computer.\nThink of a number between {} and {}.\n\
I will make a guess.\nThen please tell me if my guess is high or low.\
\nOkay, I will make a guess:".format(lower, upper))
while True:
#Computer guesses a number, it is printed
guess = math.floor(((upper + lower) / 2))
attempts += 1
print(guess)
# User input, telling computer if its guess is high or low or correct
user_feedback = str.upper(input("High(h)/Low(l)/Correct(c)? > "))
if user_feedback == "H":
upper = guess
elif user_feedback == "L":
lower = guess
elif user_feedback == "C":
print("Woohoo!!! I guessed your number \
which was {}. It took me {} attempts.".format(guess, attempts))
# play again?
replay = str.upper(input("Would you like to play again? Y/n > "))
if replay == "N":
print("OK. See you next time.")
break
else:
game()
# handle incorrect user feedback entries
else:
if user_feedback != "H" or "L" or "C":
print("please enter either H, L or C")
attempts -= 1
game()
1 Answer
Steven Parker
231,269 PointsGood idea — I did the same thing when I took that course! This way, the computer always gets the number with the minimum number of guesses.