Welcome to the Treehouse Community
The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.
HEY YOU GUYS... STEVEN I NEED YOUUUUU
Make a function named reverse_evens that accepts a single iterable as an argument. Return every item in the iterable with an even index...in reverse. For example, with [1, 2, 3, 4, 5] as the input, the function would return [5, 3, 1].
def first_4(item): return item[:4] def first_and_last_4(item): return item[:4] + item[-4::1] def odds(item): return item[1::2] def reverse_evens(item): return item[::-2]
Chris FreemanTreehouse Moderator 67,989 Points
You are on the right path. By simply taking every other item from the back of the list you may get the even indexed items or odd indexed items depending on the original length of the list. Best to use two slices: first get even indices, then reverse the first slice.
BTW, slices can be chained. For example,
collection[5:11][::2] returns item indexes 5, 7, 9
Post back if you need more help. Good luck!!
I figured out, thanks for the help!!!