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Python Python Collections (2016, retired 2019) Lists Disemvowel

Luca Tardito
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Luca Tardito
Front End Web Development Techdegree Graduate 17,602 Points
Posted by Luca Tardito
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Luca Tardito
Front End Web Development Techdegree Graduate 17,602 Points

hi guys, I don't understand where is the error in my code!

I don't know why when the word has 2 vowels nearly this function delete only the first one and leave the second one

disemvowel.py 
vowels = ["a","e","i","o","u"]
def disemvowel(word):
    word1 = list(word)
    for letter in word1:
        if letter.lower() in vowels:
            word1.remove(letter)
    return word1

1 Answer

Katie Wood
Katie Wood
19,141 Points

Hi there,

You're really close - just a couple things:

  • We want to return a string with the vowels removed, and word1 is a list - we need to convert it back into a string using .join() before we return it.

  • You generally don't want to remove values from the iterable that you are currently looping through - it can cause entries to be skipped, because it throws off the positioning of the contents. However, word1 was formed from word, and they'll have the same contents - strings are iterables too, so the solution is to loop through word, while removing values from word1.

These two things just require a couple small changes. It would look like this:

vowels = ["a","e","i","o","u"]
def disemvowel(word):
    word1 = list(word)
    for letter in word:  #iterate through word instead of word1
        if letter.lower() in vowels:
            word1.remove(letter)

    word1 = "".join(word1)  #convert word1 back into a string
    return word1