Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

iOS Swift Basics (retired) Control Flow While and Do-While Loop

Ismail Mahmoud
Ismail Mahmoud
554 Points
Posted by Ismail Mahmoud
Ismail Mahmoud
554 Points

Hi I am stuck here do not know what is the correct code, I got bummer saying your code took longtime to run

Please advise about the right code for this challenge

while_loops.swift 
let numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
var index = 0 
while index < numbers.count {println(numbers) 
}

2 Answers

Dan Johnson
Dan Johnson
40,532 Points
Dan Johnson
Dan Johnson
40,532 Points

You'll need to update index in the while loop otherwise you'll get stuck in an infinite loop.

Also you'll want to use that index to print out the specific element of the array each time.

Jhoan Arango
Jhoan Arango
14,575 Points
Jhoan Arango
Jhoan Arango
14,575 Points

Hello Ismail:

Here you are creating a while loop. Remember that a while loop will continue working until it becomes FALSE.

let numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] // Array of 10 numbers, so 
// index is from 0 to 9

var index = 0 // Here we are giving a value of 0 to a variable

while index < numbers.count {println(numbers[index]) // while the variable index is 
//less than the total numbers in the array, then print a number from the array

index++ // Add one to index. 
}

Here is how it looks without all the comments. 

let numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] 

var index = 0 
while index < numbers.count {println(numbers[index]) 
index++
}