Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

iOS Swift 2.0 Collections and Control Flow Control Flow With Conditional Statements FizzBuzz

Posted by Shannon Poulk
Shannon Poulk
2,165 Points

Hi, I do not understand why this code isnt accepted.. also i changed print for return and it will not compile. Any assi

any assistance is appreciated with this. it says double check logic for FIZZ. i am not sure what the problem is

fizzBuzz.swift 
func fizzBuzz(n: Int) -> String {
  for n in 1...100 {
        if (n % 3 == 0) && (n % 5 == 0) {
            print("FizzBuzz")
        } else if (n % 3 == 0) {
            print("Fizz")
        } else if (n % 5 == 0) {
            print("Buzz")
        } else {
            print(n)
        }
    }
  return "\(n)"
}

1 Answer

jcorum
jcorum
71,830 Points
jcorum
jcorum
71,830 Points

Close, but you were supposed to write only the function. Pasan said he'd call it. Whatever, the loop needs to be outside the function.

func fizzBuzz(n: Int) -> String {

    if n % 3 == 0 && n % 5 == 0 {
        return "FizzBuzz"
    } else if n % 3 == 0 {
        return "Fizz"
    } else if n % 5 == 0 {
        return "Buzz"
    } else {
        return "\(n)"
    }
}

for n in 1...100 {
    print(fizzBuzz(n))
}

Since the function needs to return a String the editor probably didn't like your print() statements either.