Hi I seem to have written the code and cannot see the issue could someone please help? Thanks.file:///Users/Zak/Desktop/

Hi there,

I would like to point out a few things I noticed about your code.

I would first like to explain, that I used your example to answer a question for myself - what is the difference between using print and println in Swift. I had previously recalled that println would add a space after a print statement. However, looking at stackoverflow it seems Swift 2 no long uses println. My guess is you're using XCode for Swift 2.2. http://stackoverflow.com/questions/25951195/swift-print-vs-println-vs-nslog. Just to be sure I also verified this on the Apple Developer site https://developer.apple.com/library/ios/releasenotes/General/iOS90APIDiffs/Swift/Swift.html. You can search that page for println.

Second, I would suggest using parenthesis () with your code rather than brackets []. So far I have seen brackets only used with Arrays and Dictionaries, but I am a newbie too so there may be other uses. However, to make your print statement work, try using parenthesis.

Third, if I were to re-write your original statement, the result should have been "Learning Swift Swift." this is because in your String in print you wrote "Learning Swift" before interpolating your String type constant named language. This is your code:

//Your Code    
let language = "Swift"
print("Learning Swift \(language)")
//This will print "Learning Swift Swift

As Kyle mentioned, you may want to re-write this as:

//New Code    
let language = "Swift"
print("Learning \(language)")
//This will print "Learning Swift

Or even:

//New Code 2   
let language = "swiftly"
print("Learning Swift \(language)")
//This will print "Learning Swift

Congrats, and here's to newbies learning Swift!