Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python A Social Network with Flask How to Win Friends Follow and Unfollow Buttons

Hi! I'm currently getting a syntax error, but I can't see what the issue is. Can anyone help out?

The invalid syntax traceback is showing line 61:

class Post(Model):
^

Here's my code for reference

import datetime

from flask.ext.bcrypt import generate_password_hash
from flask.ext.login import UserMixin
from peewee import *

DATABASE = SqliteDatabase('social.db')

class User(UserMixin, Model):
    username = CharField(unique=True)
    email = CharField(unique=True)
    password = CharField(max_length=100)
    joined_at = DateTimeField(default=datetime.datetime.now)
    is_admin = BooleanField(default=False)

    class Meta:
        database = DATABASE
        order_by = ('-joined_at',)

    @classmethod
    def create_user(cls, username, email, password, admin=False):
        try:
            with DATABASE.transaction():
                cls.create(
                    username=username,
                    email=email,
                    password=generate_password_hash(password),
                    is_admin=admin)
        except IntegrityError:
            raise ValueError("User already exists")     

    def get_posts(self):
        return Post.select().where(Post.user == self)

    def get_stream(self):
        return Post.select().where(
            (Post.user == self)
        )

    def following(self):
        """The users that we are following"""
        return (
            User.select().join(
                Relationship, on=Relationship.to_user
            ).where(
                Relationship.from_user == self
            )
        )

    def followers(self):
        """Get users following the current user"""
        return (
            User.select().join(
                Relationship, on=Relationship.from_user
            ).where(
                Relationship.to_user == self
        )



class Post(Model):
    timestamp = DateTimeField(default=datetime.datetime.now)
    user = ForeignKeyField(
        rel_model=User,
        related_name='posts'
    )
    content = TextField()

    class Meta:
        database = DATABASE
        order_by = ('-timestamp',)


class Relationship(Model):
    from_user = ForeignKeyField(User, related_name='relationships')
    to_user = ForeignKeyField(User, related_name='related_to')

    class Meta:
        database = DATABASE
        indexes = (
            (('from_user', 'to_user'), True)
        )

def initialize():
    DATABASE.connect()
    DATABASE.create_tables([User, Post, Relationship], safe=True)
    DATABASE.close()

[MOD: added ```python formatting -cf]

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,423 Points

Many times, the line flagged as the error follows the actual line with the error due to the syntax parsing spilling over to the next line. In this case, the error is a missing close paren in the previous statement:

return (
            User.select().join(
                Relationship, on=Relationship.from_user
            ).where(
                Relationship.to_user == self
        )  # closes where not return