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iOS Functions in Swift Adding Power to Functions Function Parameters

Daniella Flores
PLUS
Daniella Flores
Courses Plus Student 2,248 Points
Posted by Daniella Flores
Daniella Flores
Courses Plus Student 2,248 Points

Hi, the system isn't accepting my code for Functions Scope Challenge 2 of 2. Can anyone please help?

What am I doing wrong?

functions.swift 
func getRemainder(value a: Int, divisor b: Int) -> (Int) {
    return a % b
}

let result = getRemainder(value: 10, divisor: 3)

2 Answers

andren
andren
28,558 Points
andren
andren
28,558 Points

The issue is that you wrapped the return type of the function in parenthesis which you were not supposed to do. That is an issue that should have been caught during Task 1 but the task checker can let some issues through from time to time.

If you remove the parenthesis like this:

func getRemainder(value a: Int, divisor b: Int) -> Int { // Removed () around Int
    return a % b
}

let result = getRemainder(value: 10, divisor: 3)

Then your code will work.